[개념] Chapter04-2 : 파이썬 반복문 for

인프런 강의 프로그래밍 시작하기 : 파이썬 입문을 듣고 정리한 내용입니다✏️.

For문 실습

기본 For문

for v1 in range(10): # 0 ~ 9
    print('v1 is :', v1)

#v1 is : 0
#v1 is : 1
#v1 is : 2
#v1 is : 3
#v1 is : 4
#v1 is : 5
#v1 is : 6
#v1 is : 7
#v1 is : 8
#v1 is : 9

for v2 in range(1,11): # 1 ~ 10
    print('v2 is :', v2)
#v2 is : 1
#v2 is : 2
#v2 is : 3
#v2 is : 4
#v2 is : 5
#v2 is : 6
#v2 is : 7
#v2 is : 8
#v2 is : 9
#v2 is : 10

for v3 in range(1, 11, 2):
    print('v3 is :', v3)

#v3 is : 1
#v3 is : 3
#v3 is : 5
#v3 is : 7
#v3 is : 9

1 ~ 1000합

sum1 = 0
for v in range(1,1001):
    sum1 += v

print('1 ~ 1000 Sum :', sum1)
print('1 ~ 1000 Sum :', sum(range(1,1001)))
# 출력 : 1 ~ 1000 Sum : 500500

print(type(range(1,11)))
# 출력 : <class 'range'>

print('1 ~ 1000 4의배수의 합 :', sum(range(4,1001,4)))
# 출력 : 1 ~ 1000 4의배수의 합 : 125500

Iterables 자료형 반복

• 문자열, 리스트, 튜플, 집합, 사전
• iterable 리턴 함수 : range, reversed, enumerate, filter, map, zip

예제1

names = ['kim', 'Park', 'cho', 'Lee', 'Choi', 'Yoo']

for n in names:
    print('You are :', n)

#You are : kim
#You are : Park
#You are : cho
#You are : Lee
#You are : Choi
#You are : Yoo

예제2

lotto_number = [11, 19, 21, 28, 36, 37]

for n in lotto_number:
    print("Current number :", n)

#Current number : 11
#Current number : 19
#Current number : 21
#Current number : 28
#Current number : 36
#Current number : 37

예제3

word = "Beautiful"

for s in word:
    print('word :', s)

#word : B
#word : e
#word : a
#word : u
#word : t
#word : i
#word : f
#word : u
#word : l

예제4

my_info = {
    "Name" : 'Lee',
    "Age" : 33,
    "City" : 'Seoul',
}

for k in my_info:
    print('key :', k)

#key : Name
#key : Age
#key : City


for k in my_info:
    print('value :', my_info[k])
    print('value :', my_info.get(k))

#value : Lee
#value : 33
#value : Seoul

for v in my_info.values():
    print("value :", v)

#value : Lee
#value : 33
#value : Seoul

예제5

name = 'FineAppLE'

for n in name:
    if n.isupper():
        print(n)
    else:
        print(n.upper())

#F
#I
#N
#E
#A
#P
#P
#L
#E

Break

numbers = [14, 3, 4, 7, 10, 24, 17, 2, 33, 15, 34, 36, 38]

for num in numbers:
    if num == 34:
        print('Found : 34!')
        break
    else:
        print('Not found :', num)

Continue

lt = ["1", 2, 5 ,True, 4.3, complex(4)]

for v in lt:
    if type(v) is bool: # bool형이면 skip
        continue
    else:
        print("Current type:", v, type(v))

# Current type: 1 <class 'str'>
# Current type: 2 <class 'int'>
# Current type: 5 <class 'int'>
# Current type: 4.3 <class 'float'>
# Current type: (4+0j) <class 'complex'>

for-else

numbers = [14, 3, 4, 7, 10, 24, 17, 2, 33, 15, 34, 36, 38]

for num in numbers:
    if num == 55:
        print("Found : 55")
        break
else:
    print('Not Found : 55')

# Not Found : 55

구구단 출력

for i in range(2, 10):
    for j in range(1, 10):
        print('{:4d}'.format(i*j), end = '')
    print()

#   2   4   6   8  10  12  14  16  18
#   3   6   9  12  15  18  21  24  27
#   4   8  12  16  20  24  28  32  36
#   5  10  15  20  25  30  35  40  45
#   6  12  18  24  30  36  42  48  54
#   7  14  21  28  35  42  49  56  63
#   8  16  24  32  40  48  56  64  72
#   9  18  27  36  45  54  63  72  81

변환 예제

name2 = 'Aceman'

print('Reversed', reversed(name2))
# Reversed <reversed object at 0x000001B736F93BE0>

print('List', list(reversed(name2)))
#List ['n', 'a', 'm', 'e', 'c', 'A']

print('Tuple', tuple(reversed(name2)))
#Tuple ('n', 'a', 'm', 'e', 'c', 'A')

print('Set', set(reversed(name2))) # 순서X
# Set {'e', 'A', 'c', 'a', 'n', 'm'}

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